Solution 3.7 - Chemometrics: Data Analysis for the Laboratory and Chemical Plant

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  • Published: Jan 1, 2000
  • Channels: Chemometrics & Informatics

1. The area is given by 2or 3.5449

2. The width is given by 2 or 1.6651.

3. The area is 3.5453.

4. The areas are as follows. (a) 3.5450 (b) 3.5445 (c) 3.5448.

5. The principle is that the intensity is represented by a binary number, for example a 5 bit ADC means that the biggest number is 11111 or 25-1 or 31, so the largest possible number is represented by this integer. In practice in order to eliminate overflow, the receiver gain is normally set to ensure that the biggest reading never exceeds this, otherwise there can be truncation errors. All other readings are scaled to the nearest integer. There are several ways of ADC digitisation one involving truncation which is used in this case.

6. The following table shows how to do the calculation.

The last row gives the apparent integrals, note that because of truncation these are all lower than the true integrals.

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